Author Topic: Octal system (base 8)  (Read 1227 times)

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Offline Vawmataw

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Octal system (base 8)
« on: September 24, 2012, 04:23:51 pm »
How to convert a number in base 10 to a number in base 8?

Offline Tìtstewan

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Re: Octal system (base 8)
« Reply #1 on: September 24, 2012, 04:34:57 pm »
From Wikipedia: :)

For example, to convert 12510 to octal:

    125 / 82 = 1
    125 − 82 × 1 = 61
    61 / 81 = 7
    61 − 81 × 7 = 5
    5 / 80 = 5

Therefore, 12510 = 1758.

Another example:

    900 / 83 = 1
    900 − 83 × 1 = 388
    388 / 82 = 6
    388 − 82 × 6 = 4
    4 / 81 = 0
    4 − 81 × 0 = 4
    4 / 80 = 4

Therefore, 90010 = 16048.
« Last Edit: September 24, 2012, 04:43:27 pm by Tìtstewan »

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Offline Vawmataw

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Re: Octal system (base 8)
« Reply #2 on: September 24, 2012, 04:39:54 pm »
From Wikipedia: :)

For example, to convert 12510 to octal:

    125 / 82 = 1
    125 − 82 × 1 = 61
    61 / 81 = 7
    61 − 81 × 7 = 5
    5 / 80 = 5

Therefore, 12510 = 1758.

Another example:

    900 / 83 = 1
    900 − 83 × 1 = 388
    388 / 82 = 6
    388 − 82 × 6 = 4
    4 / 81 = 0
    4 − 81 × 0 = 4
    4 / 80 = 4

Therefore, 90010 = 16048.
You don't help me, because I searched that in Wikipedia, and it's not clear.

Offline Tìtstewan

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Re: Octal system (base 8)
« Reply #3 on: September 24, 2012, 04:43:09 pm »
Sorry I would write an another method:
I was too slow ...
Another exampel:
12210
    122 : 8 = 15 R - 2 at 3rd
     15 : 8 =  1 R - 7 at 2nd
      1 : 8 =  0 R - 1 at 1st

1728

You have to divide with 8.
« Last Edit: September 24, 2012, 04:56:07 pm by Tìtstewan »

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Offline Blue Elf

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Re: Octal system (base 8)
« Reply #4 on: September 25, 2012, 06:01:59 am »
The first example is a little confusing, as there's something missing:

125 / 8^2 = 1
    125 − 8^2 × 1 = 61
    61 / 8^1 = 7
    61 − 8^1 × 7 = 5
    5 / 8^0 = 5

Power mark is important. By words:
- find the highest power of 8 smaller than number you are converting (64 = 8^2 in our case)
- perform division and remember remainder: 125 / 64 = 1, remainder = 61
- repeat these steps, while decreasing number in red, until you get remainder 0:
61 / 8^1 = 61 / 8 = 7, remainder = 5
5 / 8^0 = 5 / 1 = 5, remainder = 0
Now write all result in sequence:
125(10) = 175(8 )
« Last Edit: November 27, 2012, 12:04:11 pm by Blue Elf »
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Re: Re: Octal system (base 8)
« Reply #5 on: September 25, 2012, 08:05:42 am »
Here's what I do

First, I ask myself, Is the number greater than:

4096? (zazam)
512? (vozam)
64? (zam)
8? (vol)

For example we wanna translate from English the number 59 (fifty-nine) into Na'vi octal.

59 is greater than 8 but less than 64. Therefore it's less than zam. So it's gonna be {something}vo{something}.

Next, I ask how many eights at the most are there evenly in 59?

Well, 64 is eight eights. And seven eights is 56. 56 is only a few away from 59, the number we want. It's only 3 away. So it's "seven eights and three". This is much easier to translate into Na'vi: kivopey.

Hopefully this has helped as a simple way of thinking about it / doing it.

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