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Octal system (base 8)

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Vawmataw:
How to convert a number in base 10 to a number in base 8?

Tìtstewan:
From Wikipedia: :)

For example, to convert 12510 to octal:

    125 / 82 = 1
    125 − 82 × 1 = 61
    61 / 81 = 7
    61 − 81 × 7 = 5
    5 / 80 = 5

Therefore, 12510 = 1758.

Another example:

    900 / 83 = 1
    900 − 83 × 1 = 388
    388 / 82 = 6
    388 − 82 × 6 = 4
    4 / 81 = 0
    4 − 81 × 0 = 4
    4 / 80 = 4

Therefore, 90010 = 16048.

Vawmataw:

--- Quote from: Tìtstewan on September 24, 2012, 04:34:57 pm ---From Wikipedia: :)

For example, to convert 12510 to octal:

    125 / 82 = 1
    125 − 82 × 1 = 61
    61 / 81 = 7
    61 − 81 × 7 = 5
    5 / 80 = 5

Therefore, 12510 = 1758.

Another example:

    900 / 83 = 1
    900 − 83 × 1 = 388
    388 / 82 = 6
    388 − 82 × 6 = 4
    4 / 81 = 0
    4 − 81 × 0 = 4
    4 / 80 = 4

Therefore, 90010 = 16048.

--- End quote ---
You don't help me, because I searched that in Wikipedia, and it's not clear.

Tìtstewan:
Sorry I would write an another method:
I was too slow ...
Another exampel:
12210
    122 : 8 = 15 R - 2 at 3rd
     15 : 8 =  1 R - 7 at 2nd
      1 : 8 =  0 R - 1 at 1st

1728

You have to divide with 8.

Blue Elf:
The first example is a little confusing, as there's something missing:

125 / 8^2 = 1
    125 − 8^2 × 1 = 61
    61 / 8^1 = 7
    61 − 8^1 × 7 = 5
    5 / 8^0 = 5

Power mark is important. By words:
- find the highest power of 8 smaller than number you are converting (64 = 8^2 in our case)
- perform division and remember remainder: 125 / 64 = 1, remainder = 61
- repeat these steps, while decreasing number in red, until you get remainder 0:
61 / 8^1 = 61 / 8 = 7, remainder = 5
5 / 8^0 = 5 / 1 = 5, remainder = 0
Now write all result in sequence:
125(10) = 175(8 )

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